Answer:
Explanation:
Alright, lets get started.
Suppose the distance to the park is d.
Suppose the speed is s.
Adam takes 4 hours to drive to park.
Applying speed, time , distance formula
![time=(distance)/(speed)](https://img.qammunity.org/2020/formulas/mathematics/college/2ekvtrhp4uuer66mmbfv545zviu41jrrcb.png)
![4=(d)/(s)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/vam9a0kamzsurmbzmjzxtnqm2dt9x000yu.png)
.......................... equation 1
If the speed is 45 faster, time is 2.5 times less, means
![(4)/(2.5)=(d)/(s+45)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/od12iqkzrul8bvsi0krh1a267t0znp7fdy.png)
![1.6=(d)/(s+45)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4hso1mo9s07cxfstiq1q5d1r5l2inmoawf.png)
Cross multiply
![1.6(s+45)=d](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ehmnnp92kcoz9ww7ogp3gdez6p98fwyyh9.png)
Plugging the value of s from equation 1
![1.6((d)/(4)+45)=d](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kfeld9qotnpsnzutnob6jro34ckoqt26su.png)
![1.6*(d)/(4)+1.6*45=d](https://img.qammunity.org/2020/formulas/mathematics/middle-school/d55sbqcveuh56ef31hepo5kb31pnukucgd.png)
![0.4d+72=d](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ty8mj6mu3a1t0njocyg29azi8tiy4t8cd6.png)
![0.6d=72](https://img.qammunity.org/2020/formulas/mathematics/middle-school/p1syoy1yqw3efx7urkvlhdndhziqpxy7ga.png)
![d=(72)/(0.6)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/pt2oxfgkgrva52j5ggrzb93du2nvd1ag7a.png)
![d=120](https://img.qammunity.org/2020/formulas/mathematics/middle-school/o6jh3ocsqsmv6sxdt9v2fqnydhbx7r5krv.png)
So the distance is 120 miles. : Answer
Hope it will help :)