Question

Can someone help with these?thanks!

Answer 1

QUESTION 24

The explicit formula is given as:

`a_n = 4 - 6(n - 1)`

Comparing to the formula:

`a_n = a_1 + d(n - 1)`

The common difference is d=-6.

The first term is

`a_1=4`

The recursive formula is given by

`a_n=a_(n-1)+d`

Hence the recursive formula is:

`a_n=a_(n-1) - 6 \: \: where \: \: a_1=4`

The correct answer is C

QUESTION 25

The given sequence has formula,

A(n)=5+(n-1)(6)

We can rewrite this as:

A(n)=5+6(n-1)

This implies that, the first term is

`a_1 = 5`

and the common difference is d=6

We can rewrite this formula recursively as

`a_n=a_(n-1)+d`

`a_n=a_(n-1)+6 \: \: where \: \: a_1=5`

The correct choices are:

C and D