Question

The dimensions of a box are x, 2x, and 3x. Each dimension is decreased by 2. Calculate the volume of the box.

A) 3x^3-12-8
B)-1x^6
C)6x^3-22^2+24x-8
D)40x^3

Answer 1

Correct choice is C)
`6x^3-22x^2+24x-8`.

Explanation:

Given that the dimensions of a box are x, 2x, and 3x.

Now each dimension is decreased by 2.

Then new dimensions of a box are (x-2), (2x-2), and (3x-2).

Now let's calculate the volume of the box which is given by

Volume = (Length) x (Width) x (Height)

`=(x-2)(2x-2)(3x-2)`

`=(2x^2-6x+4)(3x-2)`

`=(2x^2-6x+4)(3x-2)`

`=6x^3-22x^2+24x-8`

Hence correct choice is C)
`6x^3-22x^2+24x-8`.