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Find the sum of the following series. 14 n=1 (2n+1)

A. 448
B. 256
C. 240
D. 224

1 Answer

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ANSWER

D. 224

Step-by-step explanation

The given series is


\sum_(n=1)^(14)(2n+1)

The first term of this series is


a_1=2(1) + 1 = 3

The last term of this series is:


l = 2(14) + 1 = 29

The sum of the first n-terms of the series is calculated using the formula,


S_n= (n)/(2) (a + l)


S_ {14}= (14)/(2) (3+ 29)


S_ {14}= 7 * (32)


S_ {14}= 224

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