51.1k views
5 votes
Which statement is true?

is not a logarithmic function because the base is greater than 0.
is not a logarithmic function because the base is a square root.
is not a logarithmic function because the base is equal to 1.
is not a logarithmic function because the base is a fraction.

2 Answers

1 vote

3 is correct , base is never equal to 1 cause all of solves of logarithm will be 0

User Narendra Chouhan
by
8.1k points
2 votes

Answer with explanation:

Consider a Logarithmic Function


y=\log_(a) b\\\\y=(\log b)/(\log a)\\\\ \text{if, a=1,then}\\\\y=(\log b)/(\log 1)\\\\y=(\log b)/(0)

which is not defined.

Also,⇒ a∈(0,∞)≠1.

b> 0, that is, b∈(0,∞)

Option C:

is not a logarithmic function because the base is equal to 1.

User CJW
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories