Question

The vertex form of the equation of a parabola is y=5(x-3)^2 -6? What is the standard form of the equation? Please show steps

Answer 1

So , at first we should calculate the power because in calculating order we have:

first power or radical

then multiply or division

then + or -

so according to the rules we must do:

1)(x-3)^2=x^2 -6x +9

2)5(x^2 -6x +9)=5x^2 -30x +45

3)then -6 and we have:

Y=5x^2 -30x +39