Answer:
- The molecular formula is C₃H₆
Step-by-step explanation:
1) Assume 100 g of substace:
- Carbon, C: 85.64% × 100 g = 85.64 g
- Hydrogen, H: 14.36% × 100 g = 14.36 g
2) Convert the masses in grams to number of moles
- moles = mass in grams / atomic mass
- atomic mass of C: 12.011 g/mol
- atomic mass of H: 1.008 g/mol
Calculations:
- C: 85.64 g / 12.011 g/mol = 7.130 mol
- H: 14.36 g / 1.008 g/mol = 14.25 mol
3) State the ratio of moles.
Divide the number of moles of each element by the least number of moles:
- C: 7.130 mol / 7.130 mol = 1.0 mol
- H: 14.25 mol / 7.130 mol = 2.0 mol
4) Set the empirical formula:
5) Calculate the mass of one mol of the empirical formula:
- CH₂: 12.011 g/mol + 2× 1.088 g/mol = 14.027 g/mol
6) Calculate how many times the mass of the empirical formula is contained in the mass of the molecular formula:
- 42.08 g / 14.027 g = 2.9999 = 3
7) Set the molecular formula:
Multiply each subscript of the empirical formula by the previos ratio: 3
Conclusion: the molecular formula is C₃H₆