Question

the perimeter of a rectangular table is 132 inches the length of the table is 1 3/4 times its width what is the area of the table

Answer 1

The area of the table is
`1,008\ in^(2)`

Explanation:

Let

x----> the length of the rectangular table

y---> the width of the rectangular table

we know that

The perimeter is equal to

`P=2(x+y)`

`P=132\ in`

so

`132=2(x+y)`

`66=x+y` ------> equation A

`x=1(3)/(4)y`

`x=(1*4+3)/(4)y`

`x=(7)/(4)y` ---> equation B

substitute equation B in equation A and solve for y

`66=(7)/(4)y+y`

`66=(11)/(4)y`

`y=66*4/11=24\ in`

Find the value of x

`x=(7)/(4)(24)=42\ in`

Find the area of the table

The area is equal to

`A=xy=(42)(24)=1,008\ in^(2)`