Question

Jill weighs 15 lbs. Less than Ken. Pete weighs 50 lbs. More than Jill. Eddie weighs 18 lbs. Less than Pete. How much does each weight, if the sum of their weights is 597?

Answer 1

Jill = 125lb

Pete = 175lb

Eddie = 157lb

Ken = 140lb

Explanation:

Given

Represent Jill with J; Ken with K; Pete with P and Eddie with E

`J = K - 15`

`P = 50 +J`

`E = P - 18`

`J + K + P + E = 597`

Required

Determine the weight of each

Substitute 50 + J for P in
`E = P - 18`

`E = 50 + J - 18`

`E = J + 50 - 18`

`E = J + 32`

Make K the subject in
`J = K - 15`

`K = J + 15`

Substitute
`K = J + 15`,
`E = J + 32`,
`P = 50 +J` in
`J + K + P + E = 597`

`J + J + 15 + 50 + J + J + 32 = 597`

Collect Like Terms

`J + J +J + J = 597 - 32 - 50 - 15`

`4J = 500`

`J = 500/4`

`J = 125lb`

Substitute 125 for J in
`P = 50 +J`

`P = 50 + 125`

`P = 175lb`

Substitute 175 for P in
`E = P - 18`

`E = 175 - 18`

`E = 157`

Substitute 125 for J in
`K = J + 15`

`K = 125 + 15`

`K = 140`