Question

(3a³ - 5b³) + ? a³+ ? b³ =(a³+b³)​

Answer 1

`\boxed{-2; 6}`

Explanation:

Think of this as an ordinary addition problem.

What must you add to 3a³ to get 1a³? Answer: add -2a³

3 + (-2) = 1

What must you add to -5b³ to get 1b³? Answer: add 6b³

-5 + 6 = 1

Then, the addition looks like this:

`\begin{array}{rcr}3a^(3) & + & -5b^(3)\\\boxed{-2}a^(3) & + & \boxed{6}b^(3)\\a^(3) & + & b^{3\\\end{array}`

The numbers in the boxes are -2 and 6.