Answer:
- 14π/9; 108°; -√2/2; √2/2
Explanation:
To convert from degrees to radians, use the unit multiplier
![(\pi )/(180)](https://img.qammunity.org/2020/formulas/mathematics/high-school/yzpzo13bglfyvun8ne02xffg69rrhrmj4w.png)
In equation form that will look like this:
- 280° ×
![(\pi )/(180)](https://img.qammunity.org/2020/formulas/mathematics/high-school/yzpzo13bglfyvun8ne02xffg69rrhrmj4w.png)
Cross canceling out the degrees gives you only radians left, and simplifying the fraction to its simplest form we have
![-(14\pi )/(9)](https://img.qammunity.org/2020/formulas/mathematics/high-school/352zgwv6gu8zmhy2qpiss45sik6q0rv31b.png)
The second question uses the same unit multiplier, but this time the degrees are in the numerator since we want to cancel out the radians. That equation looks like this:
×
![(180)/(\pi )](https://img.qammunity.org/2020/formulas/mathematics/high-school/ke88cthye3evunsise1qvbe3w7rgyz3dee.png)
Simplifying all of that and canceling out the radians gives you 108°.
The third one requires the reference angle of
.
If you use the same method as above, we find that that angle in degrees is 135°. That angle is in QII and has a reference angle of 45 degrees. The Pythagorean triple for a 45-45-90 is (1, 1, √2). But the first "1" there is negative because x is negative in QII. So the cosine of this angle, side adjacent over hypotenuse, is
![-(1)/(√(2) )](https://img.qammunity.org/2020/formulas/mathematics/high-school/a5jgchmptw4ojiezkp0466brrqzhq451wd.png)
which rationalizes to
![-(√(2) )/(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/szh98xym130mffneefm1frynmizmenca44.png)
The sin of that angle is the side opposite the reference angle, 1, over the hypotenuse of the square root of 2 is, rationalized,
![(√(2) )/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/nkhqtrd1xpho9ttugw8zmwid8f33bosz4e.png)
And you're done!!!