Question

11.

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What is the standard form of the equation of a circle with center (3,-2) and radius 4?
AO (X - 3)2 + (y + 2)2 = 16
BO (x – 3)2 + (y + 2)2 = 4
C. (x + 3)2 + (y – 2)2 = 16
D. (x – 3)2 + ( – 2)2 = 16​

Answer 1

(x-3)^2+(y+2)^2=16

Step-by-step explanation:

The standard form of a circle is

`(x-h)^2+(y-k)^2=r^2`

where h and k are the coordinates of the center and r is the radius, which is squared. From our information, h is 3--> (x-3) and k is -2--> (y-(-2))--> (y+2) and 4 squared is 16. Your choice is A.

Answer 2

(x-3)^2+(y+2)^2=16

Explanation:

The standard form of a circle is

`(x-h)^2+(y-k)^2=r^2`

where h and k are the coordinates of the center and r is the radius, which is squared. From our information, h is 3--> (x-3) and k is -2--> (y-(-2))--> (y+2) and 4 squared is 16. Your choice is A.