Question

A cash register contains $5 bills and $50 bills with a total value of $1060. If there are 32 bills total, then how many of each does the register contain?

Answer 1

12 5 dollar bills

20 50 dollar bills

Explanation:

Let x = number of five dollar bills

Let y = number of fifty dollar bills

We have a total of 32 bills

x+y = 32

The total amount is 1060

5x+50y = 1060

We have 2 equations and 2 unknowns

x+y = 32

5x+50y = 1060

Multiply the first equation by -5 so we can eliminate x

-5x -5y = -5*32

-5x -5y =-160

Add this to the second equation

5x+50y = 1060

-5x -5y =-160

------------------------

45 y = 900

Divide each side by 45

45y/45 = 900/45

y = 20

There are 20 50 dollar bills

x+y = 32

x+20 = 32

Subtract 20 from each side

x+20-20 = 32-20

x = 12

There are 12 5 dollar bills