221k views
1 vote
Given the function f(x) = 2x + 6/x^2 + 5x + 6 , evaluate the function with the domain values {-3, -2, 0, 2, 3}. What is the valid domain of this function? Show all work.

User Moonglum
by
8.4k points

1 Answer

3 votes

Answer:

domain; x<0 or x>0

Explanation:

We have been given the following function;

f(x) = 2x + 6/x^2 + 5x + 6

We need to evaluate the values of f(x) for the following domain values;

{-3, -2, 0, 2, 3}

f(-3) = 2(-3) + 6/(-3)^2 + 5(-3) + 6

= -43/3

f(-2) = 2(-2) + 6/(-2)^2 + 5(-2) + 6

= -6.5

f(0) = 2(0) + 6/(0)^2 + 5(0) + 6

= undefined

f(2) = 2(2) + 6/(2)^2 + 5(2) + 6

= 21.5

f(3) = 2(3) + 6/(3)^2 + 5(3) + 6

= 83/3

The function is real and defined for every value of x in its domain except where x = 0 . This is a point of discontinuity.

Find the attachment below;

Given the function f(x) = 2x + 6/x^2 + 5x + 6 , evaluate the function with the domain-example-1
User Justmoon
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories