Answer:
B
Explanation:
Given
![\left[\begin{array}{ccc}-2&3&0\\-4&2&6\\6&-5&6\end{array}\right]](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2bu1kxz5cxw7szdjc9s0uj8lrvf1v83s96.png)
The product of 3x2 will be six.. We have a scalar which has to be multiplied by the matrix. The method of multiplying a scalar with a matrix is to multiply each element of the matrix by the scalar.
After multiplication the matrix will be:
![\left[\begin{array}{ccc}-12&18&0\\-24&12&36\\36&-30&36\end{array}\right]](https://img.qammunity.org/2020/formulas/mathematics/middle-school/fyuwgjpzc4rmhgswlcujhfdpwptdwi66cd.png)
So, B is the correct answer..