Answer:
see explanation
Explanation:
Given
6x² + x - 1 = 0 ← in standard form
To factorise the quadratic
Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term.
product = 6 × - 1 = - 6 and sum = + 1
The factors are + 3 and - 2
Use these factors to split the x- term
6x² + 3x - 2x - 1 = 0 ( factor the first/second and third/fourth terms )
3x(2x + 1) - 1(2x + 1) = 0 ← factor out (2x + 1) from each term
(2x + 1)(3x - 1) = 0
Equate each factor to zero and solve for x
2x + 1 = 0 ⇒ 2x = - 1 ⇒ x = -
3x - 1 = 0 ⇒ 3x = 1 ⇒ x =
