Question

A jeweler needs 50 ounces of a 21% silver alloy. Find the amount of a 12% silver alloy and the amount of a 24% silver alloy he should mix. Solve using a system of equation.

Need by today!! please show formula and work!!!!

Answer 1

• 12.5 ounces of 12% alloy
• 37.5 ounces of 24% alloy

Explanation:

Let x represent the amount (in ounces) of 24% alloy in the mix. Then the amount of 12% alloy is (50 -x). The amount of silver in the mix is ...

24%·x + 12%·(50 -x) = 21%·50

12x = 450 . . . . . . simplify, multiply by 100 (to eliminate %), and subtract 600

x = 37.5 . . . . . . . divide by 12

The jeweler needs to mix 37.5 ounces of 24% silver alloy with 12.5 ounces of 12% silver alloy to make 50 ounces of 21% silver alloy.