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The value of ∛x^10, when x = -2, can be written in simplest form as a∛b, where a = ___ and b = ___.

User GeLB
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2 Answers

4 votes

Person above me is right

Explanation:

User John Willemse
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2 votes

Answer:

a = -8

b = -2

Explanation:

We have been given the following radical expression;


\sqrt[3]{x^(10) }

The radical can be expressed using the law of exponents;


\sqrt[n]{x}=x^{(1)/(n) }

The radical can thus be re-written as;


\sqrt[3]{x^(10) }=(x^(10))^{(1)/(3) }

Using the law of exponents;


(a^(b))^(c)=a^(bc)

The last expression becomes;


(x^(10))^{(1)/(3) }=x^{(10)/(3) }=x^(3)*x^{(1)/(3) }\\\\=x^(3)\sqrt[3]{x}

substituting x with -2 yields;


-2^(3)\sqrt[3]{-2}=-8\sqrt[3]{-2}

User Nixmind
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