Answer:
Check attached graph
Explanation:
Given equation of the parabola is
.
Nowe we need to use the parabola tool to graph the quadratic function. Graph the parabola by first plotting its vertex and then plotting a second point on the parabola.
Compare Given equation with
we get: a=-2 and b=12
then x-coordinate of vertex
![=x=-(b)/(2a)=-(12)/(2\left(-2\right))=3](https://img.qammunity.org/2020/formulas/mathematics/high-school/8hqchggt6xdvndbf02xnbc312lon169qdd.png)
plug x=3 into given function
![y=-2x^2+12x-14](https://img.qammunity.org/2020/formulas/mathematics/high-school/vmeqyvlnl7y9z27awosktpuj5hmnf3ytpk.png)
![y=-2(3)^2+12(3)-14=4](https://img.qammunity.org/2020/formulas/mathematics/high-school/3kjtz1mb7qqjj1xg8rpm8kf144w8cnhqn7.png)
Hence vertex is (3,4).
Plug any x-value say x=0 into given function to find other point
![y=-2(2)^2+12(2)-14=2](https://img.qammunity.org/2020/formulas/mathematics/high-school/n5tr6gdsa7mom67lbs534nwk64bfoymo5v.png)
Hence second point is (2,2)
now graph the parabola using both points as shown below: