Answer:
![2.67\cdot 10^6 s](https://img.qammunity.org/2020/formulas/physics/middle-school/lv30jhxhumzzmolwo7xe8b8g2wb6foua1i.png)
Step-by-step explanation:
The radio signal travels to us at the speed of light, so at a speed of
![c=3.0\cdot 10^8 m/s](https://img.qammunity.org/2020/formulas/physics/middle-school/556h2flqn41ltgwpw2zl07hf33kpkh2pd9.png)
The distance between the spaceship and the Earth is
![d = 8\cdot 10^(14)m](https://img.qammunity.org/2020/formulas/physics/middle-school/bb5ijksj0bcz8egqpa8xkxj87f98nlr0n9.png)
Since the signal travel by uniform motion, we can write
![d = vt](https://img.qammunity.org/2020/formulas/physics/high-school/qv6awzrsbycnftlw3z5qvijk0dp45fgicp.png)
where
t is the time the signal needs to reach the Earth
By solving the equation for t, we find
![t=(d)/(v)=(8\cdot 10^(14) m)/(3.0\cdot 10^8 m/s)=2.67\cdot 10^6 s](https://img.qammunity.org/2020/formulas/physics/middle-school/675s26mna0u88f75pgf0lhh25crliaomni.png)