Question

The coordinates of three vertices of a square A (-2 1/2 , 1 1/2), B (-2 1/2 -3), and C (2,1 1/2 when point D is placed on this square what will the perimeter of the square be?

Answer 1

The perimeter of square will be 18 units

Explanation:

We are given that the coordinates of three vertices of a square A (-2 1/2 , 1 1/2), B (-2 1/2 -3), and C (2,1 1/2 )

When point D is placed on this perimeter.

We have to find the perimeter of the square.

First we have to find the side of square by using the distance formula

Distance formula

`√((x_2-x_1)^2+(y_2-y_1)^2)`

Coordinates of A=(-5/2,3/2)

Coordinates of B=(-5/2,-3)

Length of side AB=
`√((-5/2+5/2)^2+(-3-3/2)^2)`

Length of side AB=
`√(0+(-9/2)^2)`

Length of side AB=9/2 units

Now, the perimeter of square=4 (side)

Using the formula

Perimeter of square=4(9/2)=18 units