Question

A little bumblebee accelerates uniformly at 1.5 m/s² from rest to 22 m/s. Immediately upon reaching 22m/s, the brakes are applied, and it stops 2.5 s later. Find the total distance traveled.

Answer 1

190 m

Step-by-step explanation:

Displacement during acceleration:

v² = v₀² + 2a(x - x₀)

(22 m/s)² = (0 m/s)² + 2(1.5 m/s²)(x - 0 m)

x = 161.333 m

Displacement after deceleration:

x = x₀ + ½ (v + v₀)t

x = 161.333 m + ½ (0 m/s + 22 m/s)(2.5 s)

x = 188.833

Rounded to 2 sig-figs, the bumblebee travels a distance of 190 m.