104,770 views
27 votes
27 votes
2MG+O2 ...........2MGO

AR=MG=40 , O=16
calculate the mass of maganissium to form log of maganissium oxide​

User GuruBob
by
3.4k points

1 Answer

8 votes
8 votes
Mg + 1/2 O2 → MgO

1 mol = 24 g of Mg

X mol = 12 g of Mg

x = 0.5 moles of Mg

Mg :MgO = 1:1 (coefficient from equations using mole ratio)

So

0.5 moles of MgO

1 mol MgO = (24+16) g = 40 g

0.5 moles of MgO = 0.5 × 40

= 20 g of MgO produced
User Rory Nolan
by
2.3k points