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A bicycle rider increases his speed from 5 m/s to 15 m/s in while accelerating at 2.5 m/s2. How long does this take ?

User Hugtech
by
5.7k points

2 Answers

2 votes

Answer:

4 seconds

Step-by-step explanation:

Average acceleration is change in velocity over change in time:

a = Δv / Δt

Δt = Δv / a

Δt = (15 m/s - 5 m/s) / 2.5 m/s²

Δt = 4 s

User PaReeOhNos
by
5.3k points
1 vote

Answer: The time taken by the bicycle rider is 4 seconds.

Step-by-step explanation:

To calculate the time taken by the rider, we use first equation of motion:


v=u+at

where,

v = final velocity of the rider = 15 m/s

u = initial velocity of the rider = 5 m/s

a = acceleration of the car =
2.5m/s^2

t = time taken = ?

Putting values in above equation, we get:


15=5+(2.5* t)\\\\t=(15-5)/(2.5)\\\\t=4s

Hence, the time taken by the bicycle rider is 4 seconds.

User Sunil Parmar
by
6.4k points