Question

NEED ASAP

A person walks for 100 yards then turns through an angle of 60° and walks another hundred yards. How far is she from her starting point?

Please help!! I’m not sure what formula to use!!

Answer 1

`100\ yd`

Explanation:

we know that

Applying the law of cosines

`c^(2) =a^(2)+b^(2)-2(a)(b)cos(C)`

In this problem we have

c-----> is the distance from her starting point

`a=100\ yd`

`b=100\ yd`

`C=60\°`

substitute

`c^(2) =100^(2)+100^(2)-2(100)(100)cos(60\°)`

`c^(2) =10,000+10,000-10,000`

`c^(2) =10,000`

`c=100\ yd`