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Find the solutions to 2x^2+5x-3=0
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Find the solutions to 2x^2+5x-3=0

User Ed Schwehm
by
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1 Answer

3 votes

Answer:

x=1/2, x=-3

Explanation:

2x^2+5x-3 = 0

(2x^2+6x)+(-x-3) = 0

2x(x+3)+-1(x+3) = 0

(2x-1)(x+3)=0

2x-1=0, x+3=0

x=1/2, x=-3

User Aaron Mazie
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8.2k points
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