Question

How do you factor trinomials again...

Answer 1

`g^2+ 3g -10=(x-2)(x+5)`

Explanation:

The trinomial is the following

`g^2+ 3g -10`

Look for two numbers b and d that when multiplying them get as a result -10 and when you add up these numbers you get 3 as a result.

This is.

`b * d = -10\\\\b + d = 3`

Then you can write the trinomial as the product of two factors:

`(x+b)(x+d)`

You can check that the numbers that meet this condition are:

`b = -2\\d = 5`

Then the trinomial is written as

`g^2+ 3g -10=(x-2)(x+5)`