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Please help I've failed this many times

Please help I've failed this many times-example-1
User Sanghoon
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1 Answer

4 votes

Answer:

  • x-intercept (9, 0)
  • y-intercept (0, 17.5)

Explanation:

You can compute the slope from two of the points, then write the point-slope form of the equation of the line.

slope = (change in y)/(change in x)

= (15 -20)/(3 -1) = -5/2

Then the equation of the line, using the first point) is ...

y = m(x -h) +k . . . . . . for slope m through point (h, k)

y = -5/2(x -1) +20

The x-intercept is the value of x where y=0:

0 = -5/2(x -1) +20 . . .put 0 where y is in the equation, then solve for x

0 = (x -1) -8 . . . . . . . . multiply by -2/5 (the inverse of the x-coefficient)

9 = x . . . . . . . . . . . . . simplify, add 9

The x-intercept is (9, 0).

__

The y-intercept is the value of y where x=0:

y = -5/2(0 -1) +20 . . . . . . put 0 where x is in the equation, then solve for y.

y = -2.5 +20 = 17.5

The y-intercept is (0, 17.5).

_____

Comment on the problem

Your question page seems to offer both lesson and video help. Either or both may be better than the written solution here.

User Stasiaks
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4.8k points