Answer: Option D
![P (B | A) =(4)/(5)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/l12ieg4cbt6k0d71a7f1ow3p1n9hhotb2c.png)
Explanation:
Call A to the event in which a student advances to the second round.
We know that:
![P (A) = 75\% = 0.75](https://img.qammunity.org/2020/formulas/mathematics/middle-school/7xfp14iwm5jxqvckf87gsazrgvguvittlf.png)
Call B the event in which a student advances to the third round.
We know that:
![P (B) = 60\% = 0.6](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hw26t5brsmqo9kuwummsdaupiopmdmmzpr.png)
We then look for the probability of B given A. This is:
![P (B | A) =(P(B\ and\ A))/(P(A))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6n4l3rzank2lx6coctd9v6vb9zysv9smd5.png)
In this case, the probability of B and A is equal to the probability of B, since the students who advance to the third round also advanced to the second round before
![P (B | A) =(P(B))/(P(A))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hren5tcont2ovhidiymluvpyj81kydgkbd.png)
![P (B | A) =(0.6)/(0.75)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/j8072zp0qz6fqyi6umoostxkx3xg6e0j0b.png)
![P (B | A) =(4)/(5)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/l12ieg4cbt6k0d71a7f1ow3p1n9hhotb2c.png)