Question

The formula gives the height of an object in free fall at time t and acceleration g.


`h = (1)/(2)gt^(2)`

Solve for t.

`t = (2gh)^(2)`

`t = 2 √(gh)`

`t = ( √(gh) )/(2)`

`t = ( √(2hg) )/(g)`

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Answer 1

t must equal √2h/g but I don't see that in the choices above

Answer 2

t=2hg√g

Explanation:

took the test!