Question

Complete the equation of a line through (-3,3) with a slope of 1/3
y=1/3x+

Answer 1

`\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{3})~\hspace{10em} slope = m\implies \cfrac{1}{3} \\\\\\ \begin{array}c \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-3=\cfrac{1}{3}[x-(-3)] \implies y-3=\cfrac{1}{3}(x+3) \\\\\\ y-3=\cfrac{1}{3}x+1\implies y=\cfrac{1}{3}x+4`