119k views
0 votes
the pressure of a sample of helium in a 0.2 L container is 2.0atm. if the helium is compressed to a volume of 10.0 ml ,what would be the pressure of the gas?

User Davidryan
by
5.1k points

1 Answer

6 votes

Answer:

The pressure of the gas is 40atm

Step-by-step explanation:

Given parameters:

P₁ = 2.0atm

V₁ = 0.2L

V₂ = 10.0mL = 10 x10⁻³L = 0.01L

P₂ =?

We apply Boyle's law to solve this kind of problem

Boyle's law states that "the volume of a fixed mass of a gas varies inversely as the pressure changes if the temperature is constant".

It is expressed as P₁V₁ = P₂V₂

Making P₂ the subject of the formula gives:

P₂ = P₁V₁/V₂

Inserting the values of the parameters:

P₂ = 2x0.2/0.01

P₂ = 40atm

User Manuel Spigolon
by
5.6k points