Question

what will the new volume of a 22.4L same of a gas at STP if the pressure remains constant and the temperature is cut in half? A.33.6L B. 44.8L C.11.2L D. 22.4 L

Answer 1

`\boxed{\text{C. 11.2 L}}`

Step-by-step explanation:

The pressure is constant, so we can use Charles' Law to calculate the volume.

`(V_(1))/(T_(1)) = (V_(2))/(T_(2))`

Data:

V₁ = 22.4 L; T₁ = 273.15 K

V₂ = ?; T₂ = 136.58 K

Calculations:

`( 22.4)/(273.15) = ( V_(2))/(136.58)\\\\0.082 00 = ( V_(2))/(136.58)\\\\V_(2) =0.082 00 * 136.58 = \boxed{\textbf{11.2 L}}`