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Find the area of a rectangle whose side lengths are 4x*2and 6x*2-3

User Shutter
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1 Answer

5 votes

Answer:

24x^4- 12x^2 or 12x^2 (2x^2-1)

Explanation:

We are given the length and width of the rectangle:

Length=l=4x^2

and

Width=w=6x^2-3

The formula for the area of rectangle is:

Area=length*width

Area=l*w

Putting the values of l and w into the formula:

area=(4x^2 )(6x^2-3)

=24x^(2+2)-12x^2

=24x^4- 12x^2

It can also be written as: taking 12x^2 as common:

=12x^2 (2x^2-1)

User Farrukh Chishti
by
6.0k points