Question

If the voltage across a circuit of constant resistance is doubled, the power dissipated by that circuit will

Answer 1

The voltage will quadruple

Step-by-step explanation:

The power dissipated in a circuit is given by

`P=(V^2)/(R)`

where

V is the voltage

R is the resistance

In this problem, the voltage across the circuit is doubled:

V' = 2V

So the new power dissipated is

`P'=(V'^2)/(R)=((2V)^2)/(R)=4(V^2)/(R)=4 P`

so, the power dissipated will quadruple.