Solution:
Density of iron( d)=?
Specific gravity of iron=7.87
Density of water at 4°C=1g/cm^3
we have,
specific gravity =density of object/density of water at 4°C
or,7.87=d/1
or, d=7.87g/cm^3
Again,
density=mass/ volume
or,7.87=7/V
or,V=7/7.87
or,V=0.88cm^3
therefore, volume occupied by iron is 0.88cm^3