Question

Solve the equation for the interval

Answer 1

x=0,3π/2,π

Explanation:

Given

sin^2 x+sin⁡x=0

sin x is a common factor

so,

sin⁡x (sin⁡x+1)=0

We can put both factors one by one equal to zero

sin⁡x=0

x= sin^(-1)⁡0

sin⁡x is zero at 0 and π

x=0,π

sin⁡x+1=0

sin⁡x= -1

x= sin^(-1)⁡(-1)

sin is -1 for 3π/2

So,

x=3π/2

So,

x=0,3π/2,π