Question

How many grams of magnesium chloride are in 1.33 mol of MgCl2?

Answer 1

126.63 g.

Step-by-step explanation:

• Knowing that the no. of moles can be calculated using the relation:

no. of moles (n) = mass/molar mass

no. of moles MgCl₂= 1.33 mol & molar mass of MgCl₂ = 95.211 g/mol.

∴ mass = no. of moles * molar mass = (1.33 mol)*(95.211 g/mol) = 126.63 g.