Question

Please help me with this

Answer 1

294.5 m^2 to the nearest tenth.

Explanation:

First work out the area of the blue sector (not including the triangle):

The measure of the large arc = 360 - 130 = 230 degrees and the area of the Whole circle is π(11.1)^2 so, by proportion:

Area of the large sector = 230/360 * π(11.1)^2

= 247.30 m^2.

The area of the triangle = 1/2 * 11.1^2 sin 130 = 47.19 m^2.

So the area of the whole shaded region is 247.30 + 47.19

= 294.49 m^2 (answer)

Answer 2

294.5 m²

Explanation:

shaded region = area of major sector + area of triangle

central angle of major sector = 360° - 130° = 230°

area of sector = area of circle × fraction of circle

A = π × 11.1² ×
`(230)/(360)`

=
`(x11.1^2(230)\pi )/(360)` ≈ 247.3 m²

area of triangle = 0.5 × 11.1 × 11.1 × sin130° ≈ 47.2 m²

shaded area = 247.3 + 47.2 ≈ 294.5 m²