Question

What is the phase shift of y = sin(1/2 x - pi/2)?

Answer 1

π

Explanation:

The standard form of the sine function is

y = a sin(bx + c)

where a is the amplitude, period =
`(2\pi )/(b)` and

phase shift = -
`(c)/(b)`

here b =
`(1)/(2)`, c = -
`(\pi )/(2)`

phase shift = -
`(-(\pi )/(2) )/((1)/(2) )`

=
`(\pi )/(2)` × 2 = π