Answer:
2x-12/2y+3
Explanation:
Let's solve for i.
2x−5−3i=7+2yi
Step 1: Add -2iy to both sides.
−3i+2x−5+−2iy=2iy+7+−2iy
−2iy−3i+2x−5=7
Step 2: Add -2x to both sides.
−2iy−3i+2x−5+−2x=7+−2x
−2iy−3i−5=−2x+7
Step 3: Add 5 to both sides.
−2iy−3i−5+5=−2x+7+5
−2iy−3i=−2x+12
Step 4: Factor out variable i.
i(−2y−3)=−2x+12
Step 5: Divide both sides by -2y-3.
i(−2y−3)
−2y−3
=
−2x+12
−2y−3
i=
2x−12
2y+3
Answer:
i=
2x−12
2y+3