Question

1) What does Newton’s law of universal gravitation say about the distance between objects?

2) How does a free-body diagram tell you about the net force on an object?


3) Stone has a mass of 100 grams and a volume of 10 mL. Water has a density of 1 g/mL. Will the stone float or sink?


4) How does Archimedes' principle explain how much fluid is displaced by an object?


5) What does Hooke's law say about the relationship of spring to the force applied to it?


6) How can you increase the momentum of an object?


7) When is a collision considered inelastic?


8) A satellite traveling 1,000 m/s approaches a second satellite that is at rest. They both have the same mass. What will happen to their speeds when they connect and move off together?


You don't have to answer all of them just try and answer as many as you can it would be a big help ^^

Answer 1

Sorry These Are Out Of Order

"6" if you increase either mass or velocity the momentum of an object increases proportionally if you double the mass or velocity you double the momentum

"5" that it will turn to its original shape after it is let free of the force hope this helps

"4" Archimede's principle states that a body immersed in a fluid is buoyed up by a force (buoyant force) equal to the weight of the fluid displaced by the body.

So If I place a 5 oz rock into a glass of water, and 5 oz of water is displaced, the rock therefore weighs 5 oz

"3" To find if the stone will sink, we have to find out the density of the stone.

Density = mass/volume = 100g/10ml = 10g/ml

To stone will sink because it has a higher density.

"2" a free-body diagram shows the vectors for all the force acting on the body the resultant vector found by summing all the individual vectors represents the net force.

"8"

The formula for computing the final speed of a perfectly inelastic collision is

m1V1 + m2V2 = (m1 + m2)Vf

in this case the mass are equal so

m1V1 + m1V2 = (m1 + m1)Vf

m1(V1+V2) = 2(m1)Vf

thus

(m1(1000 + 0)) / 2m1 = Vf

Vf = 500 m/s

Hope my answer would be a great help for you.