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Find the area of a parallelogram with sides of 6 and 12 and an angle of 60°.

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ANSWER

36√3 square units.

Step-by-step explanation

The area of a parallelogram is obtained by multiplying the base by the height.

We use the sine ratio to obtain the height.


\sin(60 \degree) = (h)/(6)


h = 6 \sin(60 \degree)


h = 3 √(3)

The area becomes:


12 * 3 √(3) = 36 √(3) {units}^(2)

Find the area of a parallelogram with sides of 6 and 12 and an angle of 60°.-example-1
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