1 Answer

Legrandviking · Answer 1 · 2020-11-01T13:45:04+0000

Any number (except zero) raised to the power of zero is one:

11^0=1

On the other hand, by definition, the square of a number is that number multiplied by itself:

$11^2=11\cdot 11 = 121$

So, the two answer are not the same:

$11^0\\eq 11^2$

After all, the exponential function

y=11^x

is injective, which means that, given
$x_1\\eq x_2$ , we have

$11^(x_1)\\eq 11^(x_2)$

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