Question

what is the concentration of an NaOH solution that requires 50 mL of a 1.25 M H2SO4 solution to neutralize 78.0 ml of NaOH​

Answer 1

• The answer is the concentration of an NaOH = 1.6 M

Step-by-step explanation:

The most common way to solve this kind of problem is to use the formula

• C₁ * V₁ = C₂ * V₂

In your problem,

For NaOH

C₁ =?? v₁= 78.0 mL = 0.078 L

For H₂SO₄

C₁ =1.25 M v₁= 50.0 mL = 0.05 L

but you must note that for the reaction of NaOH with H₂SO₄

2 mol of NaOH raect with 1 mol H₂SO₄

So, by applying in above formula

• C₁ * V₁ = 2 * C₂ * V₂

• (C₁ * 0.078 L) = (2* 1.25 M * 0.05 L)

• C₁ = (2* 1.25 M * 0.05 L) / (0.078 L) = 1.6 M

So, the answer is the concentration of an NaOH = 1.6 M