Question

Consider the following reversible reaction

Answer 1

The right choice is K(eq) = ([CO₂]) / [O₂]

Step-by-step explanation:

The equilibrium constant of a chemical reaction is the value of its reaction quotient at chemical equilibrium

For a system undergoing a reversible reaction described by the general chemical equation

• a A + b B → x X + n N

An equilibrium constant can be expressed as following

K(eq) = ([X]ˣ*[N]ⁿ) / ([A]ᵃ*[B]ᵇ)

where [] is the equilibrium concentration of each component.

and the concentration of solid is conventionally considered as 1

in your example:

The reversible reaction

• C ₍s₎ + O₂ ₍g₎ ↔ CO₂ ₍g₎

taking in consideration that C is a solid and the concentration of solid is conventionally considered as 1

So, the equilibrium constant for this reversible reaction can be expressed as following

• K(eq) = ([CO₂]) / [O₂]

∴ The right choice is K(eq) = ([CO₂]) / [O₂]