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NEED HELP ASAP 100 POINTS!!!! A woman looks out a window of a building. She is 93 feet above the ground. Her line of sight makes an angle of theta with the building. The distance in feet of an object from the woman is modeled by the function d=93 secant theta. How far away are objects sighted at angles of 29degrees and 59degrees​?

User Ggrr
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Final answer:

To find the distance of objects sighted at angles of 29 degrees and 59 degrees, use the function d = 93 sec(theta). Substituting theta values, the distances are 106.87 feet and 166.39 feet, respectively.

Step-by-step explanation:

To find the distance of an object sighted at angles of 29 degrees and 59 degrees, we can use the function given, d = 93 sec(theta). Substituting theta = 29 degrees, we get d = 93 sec(29) = 93*(1/cos(29)) = 93/0.8714 = 106.87 feet. Similarly, substituting theta = 59 degrees, we get d = 93 sec(59) = 93*(1/cos(59)) = 93/0.5588 = 166.39 feet.

User Paul Fryer
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