Answer:
532 J
Step-by-step explanation:
If there are no frictional forces/air resistance involved in the problem, then the mechanical energy of the system is conserved.
This means that:
![E_i = E_f](https://img.qammunity.org/2020/formulas/physics/high-school/hgk837d9cl7yarlc2gflvaw51eo2s0oyjx.png)
where E_i is the initial mechanical energy and E_f is the final mechanical energy. The mechanical energy is the sum of potential energy U and kinetic energy K:
![U_i + K_i = U_f + K_f](https://img.qammunity.org/2020/formulas/physics/college/p4i2haet4dfc3f3dg5mmimcinc7ej4c0t6.png)
At the highest point, the speed of the swing is zero, so
![K_i = 0](https://img.qammunity.org/2020/formulas/physics/high-school/cgdjj6c4t7ney5jfnl65dund9cinqxuhrc.png)
while at the bottom point, the potential energy is zero (if we take the bottom point of the swing as reference level), so
![U_f =0](https://img.qammunity.org/2020/formulas/physics/college/jz01n53mkfbbyzm3oiff4tmndsmr3wwxss.png)
This means that the previous equation becomes
![U_i = K_f](https://img.qammunity.org/2020/formulas/physics/middle-school/beax5fk6018ilv0xb2dbp7ecqq94b8e6bv.png)
and since
![U_i = 532 J](https://img.qammunity.org/2020/formulas/physics/college/hwntf8j8qnr4zxmvu7zhmbrambklkvw2d0.png)
the kinetic energy at the bottom of its swing is
![K_f = 532 J](https://img.qammunity.org/2020/formulas/physics/college/2bpiq5q25r0m1yn2zbduprb7cc3r8302xr.png)