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What are the factor of 8x^3 - 27?..

User Gajus
by
8.3k points

1 Answer

2 votes

Answer:

(x - 3)(4x² + 6x + 9)

Explanation:

This is a difference of cubes which factors in general as

a³ - b³ = (a - b)(a² + ab + b²)

8x³ = (2x)³ ⇒ a = 2x

27 = 3³ ⇒ b = 3

Hence

8x³ - 27

= (2x)³ - 3³

= (2x - 3)( (2x)² + (2x × 3) + 3²)

= (2x - 3)(4x² + 6x + 9)

User Piotr Wasilewicz
by
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