Answer:
6y^2 - 20y + 6.
Explanation:
2(3y − 1)(y − 3)
= 2 [ 3y(y - 3) - 1(y - 3)]
= 2 (3y^2 - 9y - y + 3)
= 2(3y^2 - 10y + 3)
= 6y^2 - 20y + 6.
6 y² - 20 y + 6
Multiply step by step the terms inside the brackets:
3y * y
3y * -3
-1 * y
-1 * -3
add those up to get 3y² - 10 y + 3
multiply all terms of the result by 2
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